w^2-12w=-36

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Solution for w^2-12w=-36 equation: 



w^2-12w=-36

We move all terms to the left:

w^2-12w-(-36)=0

We add all the numbers together, and all the variables

w^2-12w+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$w=\frac{-b}{2a}=\frac{12}{2}=6$

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